Respuesta :
To solve this problem you must apply the proccedure shown below:
 1. You have the following information given in the problem above:
 - The spherical bubble gum ball is at the bottom
 - The radius of the cone is 1.5 inches, and its height is 3 inches.
 - The diameter of the bubble gum ball is 0.5 inches.
 2. Therefore, you must apply the formula for calculate the volume of a sphere to find the volume of the bubble gum ball:
 Vs=4πr^3/3
 r is the radius (r=0.5 inches/2=0.25 inches)
 Vs=4π(0.25 inches)^3/3
 Vs=0.065 inches^3
 3. The volume of the cone is:
 Vc=πr^2h/3
 r is the radius of the cone (r=1.5 inches)
 h is the height (h= 3 inches)
 Vc=π(1.5 inches)^2(3 inches)/3
 Vc=7.06 inches^3
 What is the closest approximation of the volume of the cone that can be filled with flavored ice?
 Vt=Vc-Vs
 Vt≈7.00 inches^3
 1. You have the following information given in the problem above:
 - The spherical bubble gum ball is at the bottom
 - The radius of the cone is 1.5 inches, and its height is 3 inches.
 - The diameter of the bubble gum ball is 0.5 inches.
 2. Therefore, you must apply the formula for calculate the volume of a sphere to find the volume of the bubble gum ball:
 Vs=4πr^3/3
 r is the radius (r=0.5 inches/2=0.25 inches)
 Vs=4π(0.25 inches)^3/3
 Vs=0.065 inches^3
 3. The volume of the cone is:
 Vc=πr^2h/3
 r is the radius of the cone (r=1.5 inches)
 h is the height (h= 3 inches)
 Vc=π(1.5 inches)^2(3 inches)/3
 Vc=7.06 inches^3
 What is the closest approximation of the volume of the cone that can be filled with flavored ice?
 Vt=Vc-Vs
 Vt≈7.00 inches^3