A compound consists of 72.2% magnesium and 27.8% nitrogen by mass. what is the empirical formula

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03-05-2018
Chemistry

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A compound consists of 72.2% magnesium and 27.8% nitrogen by mass. what is the empirical formula

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kenmyna kenmyna · Answer 1 · 2018-05-12T21:41:34+02:00

MgThe empirical formula is calculated as follows
fin the moles of each element
moles = % composition/ molar mass

magnesium(Mg) = 72.2/24 = 3moles
Nitrogen(N) = 27.8/14 = 1.986 moles

find the moles ration by dividing each mole by the smallest mole ( 1.986 moles)

that is

magnesium)Mg) = 3/1.986 = 1.5
Nitrogen (N)= 1.986/1.986 =1
multiply both the mole ratio to remove the decimal

magnesium (Mg) = 1.5 x2 = 3
nitrogen (N)= 1 x2 =2

therefore the empirical formula = Mg3N2