It is given in the question that , Triangle ABC ~ triangle DEF , and the similarity ratio is
[tex] = \frac{4}{3} [/tex]
Let DE = x
, And we will get
[tex] \frac{AB}{DE} = \frac{4}{3}
\\
\frac{60}{DE} = \frac{4}{3}
\\
DE = 60* \frac{3}{4} = 45 [/tex]
Therefore the length of DE is 45.