Answer:
b=19
Step-by-step explanation:
We are given that an equation
[tex]2x(3x+5)+3(3x+5)=ax^2+bx+c[/tex]
Given that the equation is true for all x
We have to find the value of b
[tex]2x(3x+5)+3(3x+5)=ax^2+bx+c[/tex]
[tex]6x^2+10x+9x+15=ax^2+bx+c[/tex]
[tex]6x^2+19x+15=ax^2+bx+c[/tex]
Comparing coefficients of [tex]x^2[/tex] xand constant value on both side then we get
[tex]a=6,b=19,c=15[/tex]
Hence, the value of b=19
