ABCD is a parallelogram.Find the measure of ABC
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Answer:
(C)50°.
Step-by-step explanation:
It is given that ABCD is a parallelogram and m∠ADB=38° and m∠BDC=12°.
Now, [tex]m{\angle}ADC={\angle}ADB+{\angle}BDC[/tex]
[tex]m{\angle}ADC=38^{\circ}+12^{\circ}[/tex]
[tex]m{\angle}ADC=50^{\circ}[/tex]
Also, opposite angles of parallelogram are equal, therefore m∠ADC=m∠ABC=50°.
Hence, option C is correct.