Which linear inequality is represented by the graph? y > 2/3x – 1/5 y ≥ 3/2x + 1/5 y ≤ 2/3x + 1/5 y < 3/2x – 1/5

Answer: The correct option is third, i.e., [tex]y\geq \frac{3}{2} x+\frac{1}{5}[/tex].
Explanation:
From the figure it is noticed that the line passing through the points (0,0.2) and (3,2.2).
The equation of line passing through two points is,
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)[/tex]
[tex]y-0.2=\frac{2.2-0.2}{3-0}(x-0)[/tex]
[tex]y-\frac{1}{5} =\frac{2}{3} x[/tex]
[tex]y =\frac{2}{3} x+\frac{1}{5}[/tex]
The equation of the line is [tex]y =\frac{2}{3} x+\frac{1}{5}[/tex].
From the figure it is noticed that as the value of x increases the value of y is less.
he point (1,0) lies on the shaded reason it means this point must satisfy the equation.
[tex](0)=\frac{2}{3} (1)+\frac{1}{5}[/tex]
[tex](0)=\frac{2}{3} +\frac{1}{5}[/tex]
[tex](0)=\frac{10+3}{15}[/tex]
[tex](0)=\frac{13}{15}[/tex]
It is true of the sign is less than or equal to instead of equal.
[tex]y \leq \frac{2}{3} x+\frac{1}{5}[/tex]
Therefore, option third is correct.