perimeter of a rectangle
2L + 2W = 240
Simplify, by 2:
L + W = 120
L = 120-W; use for substitution
length is decreased by 10% and breadth is increased by 20%
new dimensions
let the new length be =L - 10/100 L
= (100L - 10L) 100 = 90/100L= 9/10L
let the new breadth be = W + 20/100W
= (100W + 20W)100 = 120/100 W =12/10W
THE PERIMETER = 2L+2W =240
2(9/10L) + 2(12/10W) = 240 divided by 2
9/10L +12/10W = 120
fiirst equation L + W = 120
second equation 9/10L +12/10W = 120
so L + W = 9/10L +12/10W
THE FIRST RECTANGLE
so L = 80
W = 40
THE SECOND
L= 72cm and W= 48cm r