Identify the segment bisector of JK
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Answer:
A segment whose length is 9 units.
Step-by-step explanation:
A segment whose length is 9 units.
All we have is a bisection that divides equally segment JK in two parts. And M is the Midpoint what reassures us that JM=MK, so plugging in:
3x+15=8x+25
3x-8x=25-15
-5x=10
5x=-10
x=-2
JM=3(-2)+15 =9
MK=8(-2)+25=9