Answer : His acceleration is, [tex]-3.3m/s^2[/tex]
Explanation :
By the 1st equation of motion,
[tex]v=u+at[/tex] ...........(1)
where,
v = final velocity = 0 m/s
u = initial velocity = 10 m/s
t = time = 3 s
a = acceleration = ?
Now put all the given values in the above equation 1, we get:
[tex]0m/s=10m/s+a\times (3s)[/tex]
[tex]a=-3.3m/s^2[/tex]
Therefore, his acceleration is, [tex]-3.3m/s^2[/tex]
