Answer:
approximately 48.26 grams of water are required to generate 35.0 grams of Câ‚‚Hâ‚‚.
Explanation:
To determine the mass of water required to generate 35.0 g of Câ‚‚Hâ‚‚, we need to use the balanced equation to establish the mole ratio between Câ‚‚Hâ‚‚ and Hâ‚‚O.
The balanced equation is:
CaC₂ + 2H₂O → C₂H₂ + Ca(OH)₂
From the equation, we can see that 1 mole of Câ‚‚Hâ‚‚ is produced from 2 moles of Hâ‚‚O.
To calculate the number of moles of Câ‚‚Hâ‚‚, we divide the given mass of Câ‚‚Hâ‚‚ (35.0 g) by its molar mass (26.04 g/mol):
Moles of C₂H₂ = 35.0 g / 26.04 g/mol ≈ 1.34 mol
Using the mole ratio from the balanced equation, we can determine the moles of Hâ‚‚O required:
Moles of H₂O = 1.34 mol * (2 mol H₂O / 1 mol C₂H₂) ≈ 2.68 mol
Finally, we can calculate the mass of Hâ‚‚O by multiplying the moles of Hâ‚‚O by its molar mass (18.02 g/mol):
Mass of H₂O = 2.68 mol * 18.02 g/mol ≈ 48.26 g
Therefore, approximately 48.26 grams of water are required to generate 35.0 grams of Câ‚‚Hâ‚‚.
