Answer:
B = 41/4
A = 5/2
Step-by-step explanation:
Given information:
- Number in each box = Sum of two numbers below it (Let it be the sum law)
As shown, number below B are 5 1/2 and 4 3/45
So, B = 5 1/2 + 4 3/4 (By sum law)
- B = 11/2 + 19/4 ... Convert the whole fractions into improper fractions
- B = 22/4 +19/4 = (22+19)/4 = 41/4
For 4 3/4 the numbers below it are A and 2 1/4
So according to the problem,by the sum law,
- 4 3/4 = A + 2 1/4
- 19/4 = A + 9/4 ... Convert whole fractions to improper fractions
- A = 19/4-9/4 ... Subtract 9/4 from both sides
- A = 10/4 = 5/2 ... Cancel 2
[tex] \sf{\boxed{ \sf A = 5/2}} [/tex]
[tex] \sf {\boxed{\sf B = 41/4}} [/tex]
