Answer:
the equation of a “street” that passes through the building site and is parallel to Santa Cruz Boulevard[tex]y=\frac{x}{2}+4[/tex]
Step-by-step explanation:
- The slope is find by 2 points on line [tex](x_1,y_1)\,\text{and}\,(y_2,y_2)[/tex] is calculated as; [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
- Equation of line is in slope-intercept form is written as;
[tex](y-y_1)=m(x_2-x_1)[/tex]
We can easily take two points from given graphs are
(2,5) and (6,7)
The slope of line is;
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]m=\frac{7-5}{6-2}[/tex]
[tex]m=\frac{2}{4}[/tex]
[tex]m=\frac{1}{2}[/tex]
the slope of line is [tex]\frac{1}{2}[/tex]
Now, find the equation of line with the slope-intercept form
[tex](y-y_1)=m(x-x_1)[/tex]
[tex](y-5)=\frac{1}{2}(x-2)[/tex]
Add both the sides by 5 in above expression,
[tex]y=\frac{1}{2}(x-2)+5[/tex]
[tex]y=\frac{x}{2}-1+5[/tex]
[tex]y=\frac{x}{2}+4[/tex]
Therefore, the equation of a “street” that passes through the building site and is parallel to Santa Cruz Boulevard[tex]y=\frac{x}{2}+4[/tex]
