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the equation of line QR is y= -1/2x +1. Write an equation of a line perpenicular to line QR in slope intercept form that contains point (5,6)

A) y=2x+16

B) y= -1/2x +17/2

C) y= -1/2x +7/2

D) y=2x - 4

PLEASE PLEASE HELP!!!! I NEED THE RIGHT ANSWER!

Respuesta :

y= -1/2x +1
slope = -1/2

a line perpedicular to line QR so slope = 2

passing point (5,6)
y = mx + b
6 = 2(5) + b
so 
b = -4

equation
y = 2x - 4

answer is D) y=2x - 4

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