Answer:
The two considered triangles are similar by the AA rule of similarity.
Step-by-step explanation:
It is given that two triangles that are JKL and MNP are considered in which ∠K= ∠N,∠L= ∠P, JK=6, and MN=18.
Now, from ΔJKL and ΔMNP, we have
∠K= ∠N (Given in the question)
∠L= ∠P(Given in the question)
Thus, by AA rule of similarity,
ΔJKL is similar to ΔMNP.
Thus, the two considered triangles are similar by the AA rule of similarity.
