Respuesta :
notice the picture, after the price of quantity (x) of 5, the price begins to slant up, but before 5 is just a straight line, a steady price of 15
[tex]\bf f(x)= \begin{cases} 15,&0\ \textless \ x\le 5\\\\ 1.5x+7.5,&x\ \textgreater \ 5 \end{cases}[/tex]
[tex]\bf f(x)= \begin{cases} 15,&0\ \textless \ x\le 5\\\\ 1.5x+7.5,&x\ \textgreater \ 5 \end{cases}[/tex]

Answer:
See the graph.
Step-by-step explanation:
The function that represents the problem is
f(x) = {15 if 1≤x≤5 and 15+1.50(x-5) if x>5
and the graph is in the image, the green line is in y=15. You need to be clear that x takes integer values, but the graph shows a continuous function.
