The volume of a cylinder with a radius r and a height h:
[tex]V_1=\pi r^2h[/tex]
The volume of a cone with a radius r and a height h:
[tex]V_2=\dfrac{1}{3}\pi r^2h[/tex]
Therefore
[tex]V_2=\dfrac{1}{3}V_1[/tex]
We have [tex]V_1=32.25\ in^3[/tex]
Substitute:
[tex]V_2=\dfrac{1}{3}\cdot32.25=10.75\ in^3[/tex]
Answer: The volume of a cone is equal 10.75 in³
