Given:
The total number of marbles are 26.
Red marbles=10
Black marbles=8
Green marbles=8
The two marbles are drawn randomly,
To find the probability that both marbles are green,
The probability that first marbles chosen is green,
[tex]\begin{gathered} P=\frac{desired\text{ outcomes}}{\text{Total outcomes}} \\ P=\frac{8}{26} \end{gathered}[/tex]Condition is given that the first is not returned before the second one is drawn.
Now the we have 7 green marbles and total marbles are 25.
Probability is given by,
[tex]P=\frac{7}{25}[/tex]The total probability of getting both green marbles without replacement is,
[tex]\begin{gathered} P=\frac{8}{26}\times\frac{7}{25} \\ P=\frac{4}{13}\times\frac{7}{25} \\ P=0.08615 \end{gathered}[/tex]Answer: Probability is 0.08615.
