Force, F = 585 N
Angle, θ = 80°
The diagram that shows the resolution of the force into its rectangular component is drawn below
The magnitude of the horizontal component is:
[tex]\begin{gathered} F_x=585\sin 80 \\ F_x=585(0.9848) \\ F_x=576N \end{gathered}[/tex]
The magnitude of the vertical component is:
[tex]\begin{gathered} F_y=585\cos 80 \\ F_y=585(0.174) \\ F_y=102N \end{gathered}[/tex]
Therefore, the magnitudes of the horizontal and vertical components of the force are (576, 102)
