To understand this first, analyze the conditions of the car
[tex]\begin{gathered} v_0=\frac{10m}{s} \\ t=4s \\ a=\frac{2m}{s} \\ \\ d=\text{?} \end{gathered}[/tex]Whit this data we have to find the distance traveled by the car in these 4 seconds
[tex]\begin{gathered} d=v_0\cdot t+\frac{a\cdot t^2}{2} \\ d=10\cdot4+\frac{2\cdot4^2}{2} \\ d=40+16=56m \end{gathered}[/tex]