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A force F1 of magnitude 4.80 units acts on an object at the origin in a direction = 27.0° above the positive x-axis. (See the figure below.) A second force F2 of magnitude 5.00 units acts on the object in the direction of the positive y-axis. Find graphically the magnitude and direction of the resultant force F1 + F2.magnitude unitsdirection ° counterclockwise from the +x-axis

A force F1 of magnitude 480 units acts on an object at the origin in a direction 270 above the positive xaxis See the figure below A second force F2 of magnitud class=

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We will determine the magnitude of the final component as follows:

[tex]\begin{gathered} m=\sqrt{(5cos(27))^2+(5sin(27)+4.8)^2}\Rightarrow m=8.356527029... \\ \\ \Rightarrow m\approx8.36 \end{gathered}[/tex]

So, the magnitude is approximately 8.36.

And the direction will be approximately 57.8° counter-clockwise.

This can be seeing as follows:

Ver imagen TorrisJ194568

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