In ABCD, the measure of ZD=90°, CB = 37, BD = 12, and DC = 35. What is the valueof the sine of ZB to the nearest hundredth?
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First we need to draw the triangle:
now that we have the triangle we have to remember that the sine function is defined as:
[tex]\sin \theta=\frac{\text{opp}}{\text{hyp}}[/tex]Then, in this case we have:
[tex]\begin{gathered} \sin B=\frac{35}{37} \\ \sin B=0.95 \end{gathered}[/tex]Therefore the sine of B is 0.95 to nearest hundreth