For what of 0, in degree, is sin= con 58⁰?
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Answer: We want to find angle 'theta' for which:
[tex]\sin (\theta)=\cos (58)[/tex]In general, the following is always true:
[tex]\cos (\theta)=\sin (90-\theta)\rightarrow(1)[/tex]Therefore we have the following:
[tex]\cos (58^{\circ})=\sin (90-58)=\sin (32^{\circ})[/tex]Therefore the angles that we were interested in is:
[tex]\theta=32^{\circ}[/tex]