Given the function :
[tex]h(x)=\sqrt[3]{-x+2}[/tex]
To find which table represents the given function, let x with the numbers given in the table and find the corresponding value of h(x)
So, when x = 0
[tex]h(0)=\sqrt[3]{0+2}=\sqrt[3]{2}[/tex]
Now look to the tables which table has y = 3root of 2
We can deduce that the first two tables are wrong
Now, substitute with x = 2
[tex]h(2)=\sqrt[3]{-2+2}=\sqrt[3]{0}=0[/tex]
So, this result will be agreed with the third table
so, the answer is: Table 3
