In parallelogram DEFG, DE=6 Inches and DF= 6.4 Inches. Diagonals GE and DF Intersect at point H. If GH=4 inches, what is the length of GE?
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SOLUTION
Consider the figure below:
It is given that the diagonals DF and GE intersects at H
Recall that the daigonals of parallelogram bisect each other
It follows:
[tex]GH=HE[/tex]Since it is given that GH=4, it follows:
[tex]HE=4[/tex]Using segment addition postulate, it follows:
[tex]\begin{gathered} GE=GH+HE \\ GE=4+4 \\ GE=8 \end{gathered}[/tex]Therefore the required answer is GE=8 inches