Answer:
Area of the figure = 72mm²
Explanation:
Given:
An irregular figure
To find:
the area of the figure
To determine the area, we will divide the figure into shapes with known areas
We have 1 triangle, 1 rectangle, and 1 square. We will find the area of each of the shapes
Area of triangle = 1/2 × base × height
height = 3mm
base = 4 + 3 + 1 = 8mm
[tex]\begin{gathered} Area\text{ of the triangle = }\frac{1}{2}\times8\times3 \\ \\ Area\text{ of the traingle = 12 mm}^2 \end{gathered}[/tex]
Area of rectangle = length × width
length = 8mm, width = 3mm
[tex]\begin{gathered} Area\text{ of the rectangle = 8 }\times\text{ 3} \\ \\ Area\text{ of the rectangle = 24 mm}^2 \end{gathered}[/tex]
Area of square = length²
length = 6 mm
[tex]\begin{gathered} Area\text{ of the square = 6}^2 \\ \\ Area\text{ of the square = 36 mm}^2 \end{gathered}[/tex]
Area of the figure = Area of triangle + Area of the rectangle + Area of the square
[tex]\begin{gathered} Area\text{ of the figure = 12 + 24 + 36} \\ \\ Area\text{ of the figure = 72 mm}^2 \end{gathered}[/tex]
