Given:
The equation is,
[tex]f\mleft(x\mright)=x^2+3x-5,x=2\text{ to x = 4}[/tex]
To find: The average rate of change
Explanation:
The average rate of the change formula is,
[tex]A\left(x\right)=\frac{f\mleft(b\mright)-f\mleft(a\mright)}{b-a}[/tex]
Here, we have
[tex]\begin{gathered} a=2 \\ b=4 \end{gathered}[/tex]
Substituting we get,
[tex]\begin{gathered} A\lparen x)=\frac{f\mleft(4\mright)-f\mleft(2\mright)}{4-2} \\ =\frac{\left\lbrack4^2+3\left(4\right)-5\right?-\left\lbrack2^2+3\left(2\right)-5\right?}{2} \\ =\frac{16+12-5-\left\lbrack4+6-5\right\rbrack}{2} \\ =\frac{23-5}{2} \\ =\frac{18}{2} \\ =9 \end{gathered}[/tex]
Final answer:
The average rate of change of the given equation is 9.
