Find the area of a regular hexagon with side lengths of 12 in.
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Answer:
[tex]216\sqrt{3\text{ }}\text{ in}^2[/tex]Explanation;
Here, we want to get the area of the regular hexagon
Mathematically, we have that as:
[tex]A\text{ = }\frac{3\sqrt{3}}{2}a^2[/tex]where a represents the length of one of the sides which is 12 in
Substituting the value, we have it that:
[tex]\begin{gathered} A\text{ = }\frac{3\sqrt{3}}{2}\times\text{ 12}^2 \\ \\ A\text{ = 216}\sqrt{3\text{ }}\text{ in}^2 \end{gathered}[/tex]