How many g of oxygen are in 4.50x1024 molecules of P205?0 43.9 gO 4.24x1022 gO 600 gO 598 g
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If we have 4.50 x 10²⁴ molecules of P₂O₅, we will have 5 times as much atoms of oxygen, because in each molecule of P₂O₅ there are 5 atoms of oxygen.
So, the number of atoms of oxygenm in total, is:
[tex]5\cdot4.50\times10^{24}=22.5\times10^{24}=2.25\times10^{25}[/tex]The atomic mass of oxygen is approximately 15.9994 g/mol. So, we first need to convert the number of oxygen atoms for number of moles of oxygen.
To do that, we divide the number of atomx of oxygen by Avogadro's Numver:
[tex]N_A\approx6.022\times10^{23}mol^{-1}[/tex]So, we have:
[tex]n_O=\frac{2.25\times10^{25}}{6.022\times10^{23}mol^{-1}}=37.36300\ldots mol^{}[/tex]Now, we can convert to mass:
[tex]\begin{gathered} M_O=\frac{m_O}{n_O} \\ m_O=M_O\cdot n_O=15.9994g/mol\cdot37.36300\ldots mol=597.7856\ldots g\approx598g \end{gathered}[/tex]So, we have approximately 598 g of oxygen atom.