Graph the solution to the following inequality on the number line,(x + 6) (x-3) 20
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If you have an equality of the form...
[tex](x+a)\cdot(x-b)\ge0[/tex]The inequality can be writen as...
[tex]a\leq x\leq b[/tex]I'll show you how it looks like on the graph
the graph indicates that x is any value less than or equal to -6 or greater than or equal to 3, which is the red area
[tex]\begin{gathered} x\leq-6 \\ x\ge3 \end{gathered}[/tex]