Given
[tex]s(t)=16t^2[/tex]
Since the skydiver fell 4800ft, we need to set s(t)=4800 and solve for t, as shown below
[tex]\begin{gathered} s(t)=4800 \\ \Rightarrow16t^2=4800 \end{gathered}[/tex]
Solve for t, as follows,
[tex]\begin{gathered} \Rightarrow t^2=\frac{4800}{16}=300 \\ \Rightarrow t=\pm\sqrt{300}=\pm\sqrt{100*3}=\pm10\sqrt{3} \\ \Rightarrow t=\pm10\sqrt{3} \end{gathered}[/tex]
However, a negative time would indicate that the skydiver was falling before jumping from the plane, which is impossible.
Therefore, the only valid answer is 10sqrt(3).
The answer is 10sqrt(3)
