We are given the following formula for interest compound:
[tex]A=1000(1.023)^{2t}[/tex]Where "t" is time. We are asked to determine the value of "A" when t = 10. We replace the value of 10 in the formula, like this:
[tex]A=1000(1.023)^{2(10)}[/tex]Solving the operations
[tex]A=1000(1.023)^{20}[/tex][tex]A=1000(1.58)=1575.8[/tex]Therefore, in 10 years she will have $1575.8
