ellusA 16.9 kg monkey is swinging on a5.32 m long vine. At the bottom ofits swing, it is moving 11.3 m/s. Towhat height does it swing?(Unit = m)
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Given data
*The given mass of the monkey is m = 16.9 kg
*The length of the vine is L = 5.32 m
*The given speed is v = 11.3 m/s
The formula for the height is given by the conservation of energy as
[tex]\begin{gathered} U_k=U_p \\ \frac{1}{2}mv^2=\text{mgh} \\ h=\frac{1}{2g}\times v^2 \end{gathered}[/tex]*Here g is the acceleration due to the gravity
Substitute the values in the above expression as
[tex]\begin{gathered} h=\frac{1}{2\times\text{9}.8}\times(11.3)^2 \\ =6.5\text{ m} \end{gathered}[/tex]