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Bacteria and viruses are inactivated by temperatures above 143 ∘C in an autoclave. An autoclave contains steam at 1.00 atm and 100 ∘C .At what pressure, in atmospheres, will the temperature of the steam in the autoclave reach 143 ∘C , if n and V do not change?Express the pressure to three significant figures and include the appropriate units.

Respuesta :

Answer:

At 1.12 atm.

Explanation:

To calculate the pressure (P2), we can use the Gay-Lussac's Law replacing the values of P1 (1.00atm), T1 (100°C=373K) and T2 (143°C=416K):

[tex]\begin{gathered} \frac{P_1}{T_1}=\frac{P_2}{T_2} \\ \frac{1.00atm}{373K}=\frac{P_2}{416K} \\ 0.00268\frac{atm}{K}=\frac{P_2}{416K} \\ 0.00268\frac{atm}{K}*416K=P_2 \\ 1.12atm=P_2 \end{gathered}[/tex]

Finally, at 1.12 atm will the temperature reach 143°C.

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