If f(x) = 3x + 3, g(x) = 6x + 6, and h (x) = 9 x^2 + 18x + 9, then (f+g)(-1)=
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In order to find the value of (f+g)(-1), first let's find the composite function (f+g)(x):
[tex]\begin{gathered} (f+g)(x)=f(x)+g(x)\\ \\ =3x+3+6x+6\\ \\ =9x+9 \end{gathered}[/tex]Now, let's use x = -1 and calculate its value:
[tex](f+g)(-1)=9\cdot(-1)+9=-9+9=0[/tex]Therefore the value of (f+g)(-1) is equal to 0.