What is the length of AC if ∅=29° and BC=5? round to the nearest hundredth
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To obtain AC
[tex]\begin{gathered} \tan \text{ }\emptyset\text{ =}\frac{\text{opposite}}{\text{adjacent}} \\ \emptyset=29^0 \\ \text{opposite =5} \\ \text{adjacent = AC} \end{gathered}[/tex][tex]\begin{gathered} \tan 29^0=\frac{5}{AC}\text{ } \\ AC\text{ = }\frac{5}{\tan \text{ 29}} \\ \\ AC\text{ = }\frac{5}{0.5543} \\ \\ AC\text{ = 9.02} \end{gathered}[/tex]