In the figure, j∥k and m∠2 = 117°. What is the m∠3 ? Enter your answer in the box.
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Answer:
measure of the ∠3 is 63°.
Step-by-step explanation:
Given: j is parallel to k and t is the transversal and measure ∠2=117°.
To find: The measure of ∠3
Solution: It is given that the measure of ∠2 is 117° and from the figure, it can be seen that the ∠2 and ∠3 forms a linear pair, thus
⇒∠2 +∠3=180°
⇒117°+∠3=180°
⇒∠3=180-117
⇒∠3=63°
Therefore, the measure of the ∠3 is 63°.