Please help!!!!
Write the equation of the circle in general form. Show all your work
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Let's first gather all the information we have:
[tex]\rm\hookrightarrow Center: (-3, 2)\\\rm \hookrightarrow Radius: 5[/tex]
Let's put that into standard form [tex](x-h)^2+(y-k)^2 =r^2[/tex]
[tex]\rm \hookrightarrow Equation: (x+3)^2+(y-2)^2 = 5^2[/tex]
To put that equation into general form:
⇒ expand all the quadratics on one side and move the radius squared
to the same side as the quadratics
[tex](x+3)^2+(y-2)^2 = 25\\x^2+6x+9+y^2-4y+4=25\\x^2+y^2+6x-4y-12=0[/tex]
Answer: x² + y² + 6x - 4y - 12 = 0
Hope that helps!
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