I'm having a hard time doing inequalities, and I really need help with this question. Any help will be appreciated.
Thanks
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The solution to the given compound inequality 2x - 3 < x + 2 ≤ 3x + 5 is 5 > x ≥ -3/2
2x - 3 < x + 2 ≤ 3x + 5
solve differently
2x - 3 < x + 2
2x - x < 2 + 3
x < 5
x + 2 ≤ 3x + 5
x - 3x ≤ 5 - 2
-2x ≤ 3
x ≥ 3/-2
x ≥ -3/2
Therefore, the solution of the compound inequality is 5 > x ≥ -3/2
Learn more about compound inequality:
https://brainly.com/question/234674
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