playfulporpoise06 playfulporpoise06 03-06-2022 Mathematics contestada What are the zeros of the quadratic function f(x) = 6x² - 24x + 1? A. [tex]x = - 2 + \sqrt{ \frac{1}{2} } or \: x = - 2 \: - \sqrt{ \frac{1}{2} } [/tex]B. [tex]x = 2 + \sqrt{ \frac{1}{2} } \: or \: x = 2 - \sqrt{ \frac{1}{2} } [/tex]C.[tex]x = - 2 + \sqrt{ \frac{23}{6} } \: or \: x = - 2 - \sqrt{ \frac{23}{6} } [/tex]D.[tex]x = 2 + \sqrt{ \frac{23}{6} } \: or \: x = 2 - \sqrt{ \frac{23}{6} } [/tex]​