Could someone explain how to do this question?
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Answer:
[tex]p\left( A|B\right) =0[/tex]
Step-by-step explanation:
Formula:
[tex]p\left( A|B\right) =\frac{p\left( A\cap B\right) }{p\left( B\right) }[/tex]
The only prime outcome is 3
Then
The set A = {3}
1 and 2 are the divisors of 2
Then
The set B = {1 , 2}
Therefore , p(A∩B) = 0
Also p(B) = 0.4+0.1 = 0.5
[tex]\Longrightarrow p\left( A|B\right) =\frac{0 }{0.5 }=0[/tex]