Help please !

Write a rule to describe the function shown.

x y
โˆ’3 9
โˆ’1 3
0 0
3 โˆ’9
y = 3x
y = โˆ’3x
y equals start fraction one over three end fraction x
y equals negative start fraction one over three end fraction x

Question 2 (Multiple Choice Worth 5 points)

(04.03 MC)

What is the slope of the line joining (10, 9) and (40, 3)?

โˆ’5
โˆ’4
negative start fraction one over five end fraction
start fraction one over five end fraction

Respuesta :

Answer:

(1) Required function is ย [tex]y=-3x[/tex] . (2) Slope of line is [tex]-\frac{1}{5}[/tex] .

Step-by-step explanation:

1)

The function passing through (-3,9), (-1,3), (0,0) and (3,-9).

From these points it is noticed that the value of function decrease by 6 if the value of x increases by 2 and y-intercept is (0,0).

[tex]m=\frac{\text{change in y}}{\text{change in x}}=\frac{-6}{2}=-3[/tex]

Slope intercept of a line is

[tex]y=mx+b[/tex]

Where, m is slope and b is y-intercept.

So, function is defined as

[tex]y=-3x+0[/tex]

[tex]y=-3x[/tex]

The required function is ย [tex]y=-3x[/tex] .

2)

It is given that the line joining two points (10, 9) and (40, 3).

Slope of line is

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]m=\frac{3-9}{40-10}=\frac{-6}{30}=-\frac{1}{5}[/tex]

Therefore slope of line is [tex]-\frac{1}{5}[/tex] .