The perimeter of the polygon of sides as 9/2, 17/2, 52/5, 52/5, 64/5, 59/4 is 1227 /20.
What is the perimeter of the polygon?
The perimeter of the polygon is the measure of the sum of the sides of the given figure.
The sides are given as 9/2, 17/2, 52/5, 52/5, 64/5, 59/4
The perimeter of the polygon = 9/2 + 17/2 + 52/5 + 52/5 + 64/5 + 59/4
= 26/2 + 168/5 + 59/4
= 111/4 + 168/5
= 555 + 672 / 20
= 1227 /20
Thus, The perimeter of the polygon is 1227 /20.
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