What volume does 0.03 mol of N2 gas occupy at a temperature of 176°C and a pressure of 269 mm Hg?
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Answer:
3.12 L
Explanation:
Given the R value that is supplied
you will need to convert to atm from mm Hg and C to K
269 mm / 760 mm/atm = .354 atm
176 c = 449.15
PV = n RT
V = n RT / P = .03 * .08206 * 449.15 / .354 = 3.12 L