Find the wavelength of light given off by a hydrogen atom when its electron drops from the n = 4 to n = 1 energy level
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Find energy
[tex]\\ \rm\Rrightarrow E=-13.6\left(\dfrac{1}{6^2}-\dfrac{1}{4^2}\right)[/tex]
[tex]\\ \rm\Rrightarrow E=-13.6\left(\dfrac{1}{36}-\dfrac{1}{16}\right)[/tex]
[tex]\\ \rm\Rrightarrow E=-13.6(0.0278-0.0625)[/tex]
[tex]\\ \rm\Rrightarrow E=-13.6(-0.347)[/tex]
[tex]\\ \rm\Rrightarrow E=0.47eV[/tex]
Now
[tex]\\ \rm\Rrightarrow E=h\nu[/tex]
[tex]\\ \rm\Rrightarrow \nu=\dfrac{E}{h}[/tex]
[tex]\\ \rm\Rrightarrow \nu=\dfrac{0.47\times 10^{-19}}{6.626\times 10^{-34}}[/tex]
[tex]\\ \rm\Rrightarrow \nu=0.071\times 10^{15}[/tex]
[tex]\\ \rm\Rrightarrow \nu=7.1\times 10^{13}Hz[/tex]