please help me with this, I will give brainliest.
find the value of x round to the nearest 10th
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[tex]\tan x = \dfrac{\text{Opposite}}{\text{Adjacent}}\\\\\implies \tan x = \dfrac{12}{6}\\\\\implies \tan x = 2\\\\\implies x = \tan^{-1} (2)=63.4^\circ[/tex]
Answer:
x ≈ 63.4°
Step-by-step explanation:
using the tangent ratio in the right triangle.
tan x = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{12}{6}[/tex] = 2 , then
x = [tex]tan^{-1}[/tex] ( 2) ≈ 63.4° ( to the nearest tenth )