How do I find leg sizes with hypotenuse given of a 45,90,45 triangle
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Answer:
about 2.47487
Step-by-step explanation:
1. [tex]u\sqrt{2} =\frac{7}{2}[/tex]
2. [tex]u=\frac{7\sqrt{2} }{4}[/tex]
3. Simplify to about 2.47487
*the hypotenuse of a 45-45-90 triangle is always the leg length (x), root 2. Ex: leg=4, hypotenuse=4(root 2)