If 2.0 g of copper(II) chloride react with excess sodium nitrate, what mass of sodium chloride is formed in this double replacement reaction? Write the balanced equation for the reaction first.

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

CuCl₂: 1 mole
NaNO₃: 2 moles
Cu(NO₃)₂ : 1 mole
NaCl: 2 moles

The molar mass of the compounds is:

CuCl₂: 134.44 g/mole
NaNO₃: 85 g/mole
Cu(NO₃)₂ : 187.54 g/mole
NaCl: 58.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

CuCl₂: 1 mole ×134.44 g/mole= 134.44 grams
NaNO₃: 2 moles ×85 g/mole= 170 grams
Cu(NO₃)₂ : 1 mole ×187.54 g/mole= 187.54 grams
NaCl: 2 moles ×58.45 g/mole= 116.9 grams

Mass of NaCl formed

The following rule of three can be applied: If by stoichiometry of the reaction 134.44 grams of CuCl₂ form 116.9 grams of NaCl, 2 grams of CuCl₂ form how much mass of NaCl?

[tex]mass of NaCl=\frac{2 grams of CuCl_{2}x116.9 grams of NaCl }{134.44grams of CuCl_{2}}[/tex]

mass of NaCl= 1.739 grams

Finally, 1.729 grams of NaCl is formed.

Learn more about the reaction stoichiometry:

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