Help please ! It’s geometry
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Answer:
[tex]x = 11 \sqrt{2} [/tex]
[tex]y = 11 \sqrt{2} [/tex]
Step-by-step explanation:
[tex] \sin(45) = \frac{y}{22} \\ \\ \frac{1}{ \sqrt{2} } = \frac{y}{22} \\ \\ y = \frac{22}{ \sqrt{2} } \\ \\ y = 11 \sqrt{2} [/tex]
[tex] \cos(45) = \frac{x}{22} \\ \\ x = 11 \sqrt{2} [/tex]