Respuesta :

Answer:

[tex]\frac{\sqrt{10} }{2}[/tex]

Step-by-step explanation:

Using cosine (since that is adjacent over hypotenuse), cos(60)=1/2 so your answer is hypotenuse*1/2=[tex]\sqrt{10}*\frac{1}{2}=\frac{\sqrt{10} }{2}[/tex]

fieryanswererft

Answer:

[tex]x = \frac{\sqrt{10} }{2}[/tex]

Step-by-step explanation:

Using Pythagoras Theorem:

The triangle has hypotenuse of √10 , opposite side x, angle 30°

Using the formula:

                                   [tex]sin(A) = \frac{opposite}{hypotenuse}[/tex]

                                   [tex]sin(30)= \frac{x}{\sqrt{10} }[/tex]

                                    [tex]x = sin(30) * \sqrt{10}[/tex]

                                    [tex]x = \frac{\sqrt{10} }{2}[/tex]

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