Find value of x when y = 1
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Answer:
x = 3.2
Explanation:
when y = 1
1 = x²-2x-3
x²-2x-3-1 = 0
x²-2x-4 = 0
[tex]x = \frac{ 2 \pm \sqrt{(-2)^2 - 4(1)(-4)}}{2*1}[/tex]
[tex]x = 1 + \sqrt{5}[/tex]
x = 3.236
x = 3.24 in 2 decimal places
x = 3.2 in nearest tenth